Saw this on Facebook, and I thought it's fake.

But out of curiosity, I went to google '

Batman equation", and found that somebody actually solve it!!

These people are brilliant...

And the prof who came out with this equation is genius.

Solution taken from

HERE:

The ellipse

(x7)2+(y3)2−1=0 looks like this:

So the curve

(x7)2∣∣∣∣x∣∣−3∣∣∣∣x∣∣−3−−−−−√+(y3)2∣∣y+333√7∣∣y+333√7−−−−−−√−1=0 is the above ellipse, in the region where

|x|>3 and

y>−333−−√/7:

That's the first factor.

The second factor is quite ingeniously done. The curve

∣∣x2∣∣−(333√−7)112x2−3+1−(||x|−2|−1)2−−−−−−−−−−−−−−−√−y=0 looks like:

This is got by adding

y=∣∣x2∣∣−(333√−7)112x2−3, a parabola on the positive-x side, reflected:

and

y=1−(||x|−2|−1)2−−−−−−−−−−−−−−−√, the upper halves of the four circles

(||x|−2|−1)2+y2=1:

The third factor

9(∣∣(1−∣∣x∣∣)(∣∣x∣∣−.75)∣∣)(1−∣∣x∣∣)(∣∣x∣∣−.75)−−−−−−−−−−−−√−8|x|−y=0 is just the pair of lines y = 9 - 8|x|:

truncated to the region

0.75<|x|<1.

Similarly, the fourth factor

3|x|+.75(∣∣(.75−∣∣x∣∣)(∣∣x∣∣−.5)∣∣(.75−∣∣x∣∣)(∣∣x∣∣−.5))−−−−−−−−−−−−−−√−y=0 is the pair of lines

y=3|x|+0.75:

truncated to the region

0.5<|x|<0.75.

The fifth factor

2.25∣∣(.5−x)(x+.5)∣∣(.5−x)(x+.5)−−−−−−−−−√−y=0 is the line

y=2.25 truncated to

−0.5<x<0.5.

Finally,

610√7+(1.5−.5|x|)−(610√)144−(|x|−1)2−−−−−−−−−−−√−y=0 looks like:

so the sixth factor

610√7+(1.5−.5|x|)∣∣∣∣x∣∣−1∣∣∣∣x∣∣−1−−−−−√−(610√)144−(|x|−1)2−−−−−−−−−−−√−y=0 looks like

As a product of factors is

0 iff any one of them is

0, multiplying these six factors puts the curves together, giving: (the software, Grapher.app, chokes a bit on the third factor, and entirely on the fourth)

## 4 comments:

siao

but very impressive, no?

coz i dont need it, so didnt impress me..

Then let's ask the math teacher.

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